9e6d25b27b786d3f8ceba16a39ceeb5b0d574caa — kotrunga 5 months ago a398138
completed loops and func exercise
1 files changed, 51 insertions(+), 0 deletions(-)

A basics/flow-control-statements/1.2.8_exercise-loops-and-functions.go
A basics/flow-control-statements/1.2.8_exercise-loops-and-functions.go => basics/flow-control-statements/1.2.8_exercise-loops-and-functions.go +51 -0
@@ 0,0 1,51 @@
+ /*
+ 	Notes 1.2.8
+ 
+ 	- Implement a square root function with loops and functions
+ 	- Using the variable name 'z', just following the AToG example
+ */
+ 
+ package main
+ 
+ import (
+ 	"fmt"
+ 	"math"
+ )
+ 
+ func Sqrt(x float64) float64 {
+ 	var z float64 = 1
+ 	for i := 0; i < 10; i++ {
+ 		//fmt.Println(z)	// uncomment to see z become more precise
+ 		z -= (z*z - x) / (2 * z)
+ 	}
+ 	return z
+ }
+ 
+ /*
+ 	Here, we loop until the difference between the
+ 	z and the previous z is less than 1E-10
+ */
+ func SqrtAccurate(x float64) float64 {
+ 	var z float64 = 1
+ 	var z_previous float64 = 0
+ 	var threshold float64 = 0.0000000001	// 1E-10
+ 
+ 	for math.Abs(z - z_previous) >= threshold {
+ 		//fmt.Println(z)	// uncomment to see z become more precise
+ 		z_previous = z
+ 		z -= (z*z - x) / (2 * z)
+ 	}
+ 
+ 	return z
+ }
+ 
+ func main() {
+ 	fmt.Printf("Sqrt(%d) = %g\n", 2, Sqrt(2))
+ 	fmt.Printf("SqrtAccurate(%d) = %g\n\n", 2, SqrtAccurate(2))
+ 
+ 	fmt.Printf("Sqrt(%d) = %g\n", 2435, Sqrt(2435))
+ 	fmt.Printf("SqrtAccurate(%d) = %g\n\n", 2435, SqrtAccurate(2435))
+ 
+ 	fmt.Printf("Sqrt(%d) = %g\n", 25, Sqrt(25))
+ 	fmt.Printf("SqrtAccurate(%d) = %g\n\n", 25, SqrtAccurate(25))
+ }< 
\ No newline at end of file