3 files changed, 125 insertions(+), 33 deletions(-)

R hw6.ipynb => .ipynb_checkpoints/mainscript-checkpoint.ipynb
D Untitled.ipynb
A mainscript.ipynb

@@ 1,33 0,0 @@
-{
- "cells": [
-  {
-   "cell_type": "code",
-   "execution_count": null,
-   "id": "d357a88a-ee5c-40ae-9cb2-b1f902fda60a",
-   "metadata": {},
-   "outputs": [],
-   "source": []
-  }
- ],
- "metadata": {
-  "kernelspec": {
-   "display_name": "Python 3",
-   "language": "python",
-   "name": "python3"
-  },
-  "language_info": {
-   "codemirror_mode": {
-    "name": "ipython",
-    "version": 3
-   },
-   "file_extension": ".py",
-   "mimetype": "text/x-python",
-   "name": "python",
-   "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython3",
-   "version": "3.11.7"
-  }
- },
- "nbformat": 4,
- "nbformat_minor": 5
-}

@@ 0,0 1,125 @@
+{
+ "cells": [
+  {
+   "cell_type": "code",
+   "execution_count": 76,
+   "id": "68d95f7e-e869-4b32-a487-292d85e5c4ee",
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "\n",
+      "\u001b[1m equation1 \u001b[0m is i₁⋅(6.0 - 8.0⋅ⅉ) + (6.0 - 8.0⋅ⅉ)⋅(i₁ - i₂) - 675.0 - 389.711431\n",
+      "702997⋅ⅉ\n",
+      "\u001b[1m equation2 \u001b[0m is i₂⋅(6.0 - 8.0⋅ⅉ) + (6.0 - 8.0⋅ⅉ)⋅(-i₁ + i₂) + 779.422863405995⋅\n",
+      "ⅉ\n",
+      "\u001b[1m solutions \u001b[0m is [{i₁: 27.0 + 36.0⋅ⅉ, i₂: 44.6769145362398 - 5.38268590217986⋅ⅉ}\n",
+      "]\n",
+      "\u001b[1m This will print the symbols of the variable, not the variable. Look at your symbols above. \u001b[0m\n",
+      "\u001b[1m i1 \u001b[0m rectangular form is (27.00000000000003+35.99999999999998j)\n",
+      "\u001b[1m i1 \u001b[0m phasor form is 45.0 ∠ 53.13°\n",
+      "\n",
+      "\u001b[1m i2 \u001b[0m rectangular form is (44.67691453623981-5.38268590217986j)\n",
+      "\u001b[1m i2 \u001b[0m phasor form is 45.0 ∠ -6.87°\n",
+      "\n",
+      "\u001b[1m i2-i1 \u001b[0m rectangular form is (17.676914536239785-41.38268590217984j)\n",
+      "\u001b[1m i2-i1 \u001b[0m phasor form is 45.0 ∠ -66.87°\n",
+      "\n",
+      "\u001b[1m i2 * -1 \u001b[0m rectangular form is (-44.67691453623981+5.38268590217986j)\n",
+      "\u001b[1m i2 * -1 \u001b[0m phasor form is 45.0 ∠ 173.13°\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "import electricpy as ep\n",
+    "from sympy import symbols, Eq, solve, I\n",
+    "from varname import varname\n",
+    "from __future__ import print_function\n",
+    "from io import StringIO\n",
+    "import sys\n",
+    "from sympy import init_session\n",
+    "\n",
+    "init_session(quiet=True) \n",
+    "#TODO fix making printing and enetering more expressions more elegant\n",
+    "\n",
+    "def equation_print(name, variable):\n",
+    "    # weird codes are just bolding and unbolding\n",
+    "    print('\\033[1m', name, '\\033[0m', 'is ', end=\"\")\n",
+    "    pprint(variable, imaginary_unit = \"j\")\n",
+    "    \n",
+    "def print_rect_and_phasor(name, value):\n",
+    "    value = complex(value)\n",
+    "    print('\\033[1m', name, '\\033[0m', \"rectangular form is\", value)\n",
+    "    print('\\033[1m', name, '\\033[0m', \"phasor form is \", end =\"\")\n",
+    "    ep.cprint(value)\n",
+    "    print()\n",
+    "    \n",
+    "#declare what things you want to solve for. If I have i1, i2, v1, and v2, but I only need i1 and i2, \n",
+    "#I will only add those to varlist\n",
+    "varlist = [i1,i2]\n",
+    "\n",
+    "i1 = symbols('i1')\n",
+    "i2 = symbols('i2')\n",
+    "\n",
+    "#write your equations here \n",
+    "equations = [equation1, equation2]\n",
+    "equation1 = (ep.phasor(-450, 0) + ((6-8j) * (i1)) + ((6-8j) * (i1-i2)) + ep.phasor(450, -120))\n",
+    "equation_print('equation1', equation1)\n",
+    "\n",
+    "equation2 = (ep.phasor(-450,-120) + (6-8j) * (i2-i1) + i2 * (6-8j) + (ep.phasor(450,120)))\n",
+    "equation_print('equation2', equation2)\n",
+    "\n",
+    "#solve the equations\n",
+    "solutions = solve(equations, varlist, dict=True)\n",
+    "equation_print('solutions', solutions)\n",
+    "\n",
+    "#print the solutions\n",
+    "print('\\033[1m', \"This will print the symbols of the variable, not the variable. Look at your symbols above.\", '\\033[0m')\n",
+    "solutions = solutions[0]\n",
+    "for count, value in enumerate(varlist):\n",
+    "    temp = solutions[value]\n",
+    "    temp = complex(temp)\n",
+    "    print_rect_and_phasor(value,temp)\n",
+    "    \n",
+    "\n",
+    "#Get whatever else you need\n",
+    "#TODO: make this more elegant\n",
+    "s = solutions\n",
+    "print_rect_and_phasor('i2-i1', s[i2]-s[i1])\n",
+    "print_rect_and_phasor('i2 * -1', s[i2] * -1)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "id": "f569a832-f0b8-422b-8075-7ba70211a085",
+   "metadata": {},
+   "source": [
+    "y"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.11.7"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 5
+}